 admin # A light source emits a beam of photons, each of which has a momentum of 2.7 × 10-29 kg·m/s. (a) what is the frequency of the photons? (b) to what region of the electromagnetic spectrum do the photons belong?

2 months ago

## Solution 1 Guest #4171
2 months ago

The frequency of the photons is equal to 1.22 ×10¹³ Hz and lies in the infrared region of the electromagnetic spectrum.

### What is the frequency?

The frequency of the photons or light can be described as the number of oscillations in one second. The frequency possesses S.I. units per second or Hertz.

The relationship between momentum (p), frequency (ν), and speed of light (c) is:

p = hν/c

ν = pc/h

Given, the momentum of the photons, p = 2.7 ×10⁻²⁹ Kg.m/s

The speed of light, c = 3×10⁸ m/s

The plank's constant, h = 6.626 ×10⁻³⁴ Js

The frequency of the photons can determine from the above-mentioned relationship:

ν = (2.7 × 10⁻²⁹).( 3 × 10⁸)/ 6.626 × 10⁻³⁴

ν = 1.22 × 10¹³ Hz

Therefore, the frequency of the photons is 1.22 × 10¹³ Hz and lies in the infrared region of the spectrum.

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## Solution 2 Guest #4172
2 months ago
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Solution 2
4. protons are positively charged.

In fact, the direction of the electric field of a charged particle depends on the sign of the charge of the particle. While a negatively charged particle (such as the electron) produces an electric field that points toward the charge, a positively charged particle (like a proton) produces an electric field that points away from the charge. This can be proofed by using a positive test charge: if we put a positive test charge near a proton, this test charge will move away from the proton (because it is repelled from it, since they have same charge), and the direction of its motion gives the direction of the electric field generated by the proton, so away from it.
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Can be formulated I = intensity, W m⁻²

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