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A light source emits a beam of photons, each of which has a momentum of 2.7 × 10-29 kg·m/s. (a) what is the frequency of the photons? (b) to what region of the electromagnetic spectrum do the photons belong?

2 months ago

Solution 1

Guest #4171

2 months ago

The frequency of the photons is equal to 1.22 ×10¹³ Hz and lies in the infrared region of the electromagnetic spectrum.

What is the frequency?

The frequency of the photons or light can be described as the number of oscillations in one second. The frequency possesses S.I. units per second or Hertz.

The relationship between momentum (p), frequency (ν), and speed of light (c) is:

p = hν/c

ν = pc/h

Given, the momentum of the photons, p = 2.7 ×10⁻²⁹ Kg.m/s

The speed of light, c = 3×10⁸ m/s

The plank's constant, h = 6.626 ×10⁻³⁴ Js

The frequency of the photons can determine from the above-mentioned relationship:

ν = (2.7 × 10⁻²⁹).( 3 × 10⁸)/ 6.626 × 10⁻³⁴

ν = 1.22 × 10¹³ Hz

Therefore, the frequency of the photons is 1.22 × 10¹³ Hz and lies in the infrared region of the spectrum.

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Solution 2

Guest #4172

2 months ago

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A gravitational field vector points toward the earth; an electric field vector points toward an electron. why do electric field vectors point away from protons? 1. protons have much larger mass. 2. unlike electrons, protons will produce an electric field of their own. 3. protons have more net charge than electrons. 4. protons are positively charged. 5. none of these

Solution 1

The electric field vectors point away from protons because protons are positively charged. Option 4 is the correct option.

What is electric field?

The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.

When the two charges or the charged bodies interact each other, the force of attraction or repulsion acts between them. This force of attraction or repulsion can be find out using the coulombs law.

This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-

Like charges-For the like charges, when two charges interact to each other, then the charges repel each other.
Unlike charges-For the unlike charges, when two charges interact to each other, then the charges attract each other.

A gravitational field vector points toward the earth; an electric field vector points toward an electron.

It is known that the charge of electron is negative. The electric filed vector is attracted towards the electron, this ,means the charge of it should be positive (unlike charge to electron to attract it).

Now this electric field vectors point away from protons, as this both become same or like charges (positive).

Thus, the electric field vectors point away from protons because protons are positively charged. Option 4 is the correct option.

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Solution 2

The correct answer is
4. protons are positively charged.

In fact, the direction of the electric field of a charged particle depends on the sign of the charge of the particle. While a negatively charged particle (such as the electron) produces an electric field that points toward the charge, a positively charged particle (like a proton) produces an electric field that points away from the charge. This can be proofed by using a positive test charge: if we put a positive test charge near a proton, this test charge will move away from the proton (because it is repelled from it, since they have same charge), and the direction of its motion gives the direction of the electric field generated by the proton, so away from it.

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A crying baby emits sound with an intensity of 8.0 × 10-8 w/m2. calculate a reasonable estimate for the intensity level from a set of quintuplets (five babies), all crying simultaneously at the same place? the lowest detectable intensity is 1.0 × 10-12 w/m2.

Solution 1

Sound intensity of 1 baby, I = 8*10^-8 W/m^2

The sound heard should be higher by:

10*log (n) where for 5 babies, n = 5. Then
10*log (n) = 10*log (5) ≈ 7 dB

Also give is the reference sound, Io = 1.0*10^-12 W/m^2

Therefore,
Sound intensity, L1 = 10*log (I/I1) = 10*log [(8*10^-8)/(1*10^-12)] ≈ 49 dB
Therefore, total intensity for the five babies is:

Total intensity = 49+7 = 56 dB

Solution 2

The intensity level from a set of quintuplets (five babies) : 56 dB

Further explanation

Wave intensity is the power of a wave that is moved through a plane of one unit that is perpendicular to the direction of the wave

Can be formulated

$\rm I=\dfrac{P}{A}$

I = intensity, W m⁻²

P = power, watt

A = area, m²

The farther the distance from the sound source, the smaller the intensity

$\rm \dfrac{I_2}{I_1}=\dfrac{(r_1)^2}{(r_2)^2}$

So the intensity is inversely proportional to the square of the distance from the source

$\rm I\approx \dfrac{1}{r^2}$

Intensity level (LI) can be formulated

$\rm LI=10\:log\dfrac{I}{I_o}$

Io = 10⁻¹²

For the level of intensity of several sound sources as many as n pieces can be formulated:

LIn = LI1 + 10 log n

The intensity level of 1 baby is

$\rm LI=10\:log\dfrac{8.10^{-8}}{10^{-12}}$

LI = 10 log 8.10⁴

LI = 49

The intensity level of 5 babies :

LI5 = LI + 10 log n

LI5 = 49 + 10 log 5

LI5 = 49 + 7

LI5 = 56

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When n resistors are connected in parallel, it means they are connected to the same potential difference V:
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It also means that the total current in the circuit is given by the sum of the currents flowing through each branch (each resistor) of the circuit:
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By using Ohm's law:
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we can rewrite (1) as
$\frac{V}{R_{eq}} = \frac{V_1}{R_1}+ \frac{V_2}{R_2}+...+ \frac{V_n}{R_n}$
However, we said that the potential difference across each resistor is equal (eq.(2)), so we can rewrite the last formula as
$\frac{V}{R_{eq}} = \frac{V}{R_1}+ \frac{V}{R_2}+...+ \frac{V}{R_n}$
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A cello string 0.75 m long has a 220 hz fundamental frequency. find the wave speed along the vibrating string. answer in units of m/s.

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For fundamental frequency of a string to occur, the length of the string has to be half the wavelength. That is,

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Solution 2

The equivalent resistance of several devices connected in parallel is given by
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tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
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therefore if there are too many devices connected in parallel, this can be a problem because there could be too much power dissipated (and too much heat) through the circuit.

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Apply: what will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors? test your answers with the gizmo.

Solution 1

1) Total resistance

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where $R_i$ are the single resistances.

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2) Current in the circuit

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Solution 2

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