The solution region of the inequalities y > 2x - 3 and y < 2x + 4 would be the region between the parallel lines y = 2x - 3 and y = 2x + 4.
Linear Inequalities are the statements in mathematics where the left and right hand side are separated using inequality symbols like <, >, ≤ and ≥.
We have the system of inequalities given here:
y > 2x - 3 and
y < 2x + 4
To solve this first take the inequalities as equations y = 2x - 3 and y = 2x + 4.
Take y = 2x - 3
When x = 0, then y = -3
When x = 1, then y = -1
When y = 0, then x = 1.5
We get three points here (0, -3), (1, -1) and (1.5, 0).
Draw a line passing through these points.
Substitute (x, y) as (0, 0), then the inequality y > 2x - 3 become 0 > -3, which is true. Therefore solution region is the region containing the origin.
Similarly, take y = 2x + 4.
When x = 0, then y = 4
When x = 1, then y = 6
When y = 0, then x = -2
We get three points here, (0, 4), (1, 6) and (-2, 0).
Substitute (x, y) as (0, 0), then the inequality y < 2x + 4 become 0 < 4, which is true. Therefore solution region is the region containing the origin.
Hence the solution region of these inequalities would be the region lower to the line y = 2x + 4 and the region upper to the line y = 2x - 3.
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Second option on e2020
Step-by-step explanation:
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(x,y) → (-(y-6), -x + 6)