you would have to do out the equation of 117 divided by 6.5 which would give you 18 feet per second
What logarithmic equation has the same solution as x-4=2^3
Solution:
x-4=2³
x-4=2*2*2
x-4=8
TO solve for x, Let us add 4 on both sides
x-4+4=8+4
x+0=12
So, x=12
But, x=12 is not a logarithmic equation and there are no options
So, an equation like, x=㏒
As log has base 10,
So, x=㏒ =12
So, logarithmic equation like x=log has same solution as x-4=2³
Answer:
is required lograthmic equation.
Step-by-step explanation:
Given: Given equation, x - 4 = 2³
To find: Logarithmic function whose solution is same as given equation.
First we find the solution of given Equation.
consider,
x - 4 = 2³
x - 4 = 8 ( ∵ 2³ = 2×2×2 = 8 )
x = 8 + 4 ( Transposing 4 to RHS )
x = 12
Now we find the logarithmic equation whose solution is also x = 12.
( There exist many such equations )
Lets say one of them is,
Now we find its solution to check if it is same or not.
(using lograthmic rule,
)
⇒ 2 × ( x + 2 ) = 28 (using lograthmic rule, )
⇒ 2x + 4 = 28
⇒ 2x = 28 - 4 (transposing 4 to RHS)
⇒ 2x = 24 (transposing 2 to RHS)
⇒
⇒ x = 12
Therefore, is required lograthmic equation.
The solution for the given system of equations are (6, 20).
A system of linear equations is a set of two or more equations involving two or more variables. All of the equations must be considered at once in order to find the solution, which is any pair of values that makes each equation true independently.
The given system of linear equations are y=x+14 -----(i) and y=3x+2 -----(ii).
From equation (i) and (ii), we get
x+14=3x+2
3x-x=14-2
2x=12
x=6
Substitute x=6 equation (i), we get
y=20
Therefore, the solution for the given system of equations are (6, 20).
To learn more about the linear system of an equations visit:
brainly.com/question/27664510.
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Answer:
(6, 20), because both lines pass through this point
Step-by-step explanation:
We see that both equations are equal to y. This means we can set the two equations equal to each other:
x+14 = 3x+2
Subtract x from each side:
x+14-x = 3x+2-x
14 = 2x+2
Subtract 2 from each side:
14-2 = 2x+2-2
12 = 2x
Divide both sides by 2:
12/2 = 2x/2
6 = x
Substitute this into the first equation:
y = x+14
y = 6+14
y = 20
This makes the solution (6, 20).