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How do i solve 3 (2y-4)=8y+9-9y

How do i solve 3 (2y-4)=8y+9-9y

2 months ago

Solution 1

Guest Guest #3558
2 months ago
3(2y - 4) = 8y + 9 - 9y

Distribute 3:
6y - 12 = 8y + 9 - 9y

Combine like terms:
6y - 12 = -y + 9

Add y to both sides:
7y - 12 = 9 

Add 12 to both sides:
7y = 21

Divide both sides by 3:
y = 3

Solution 2

Guest Guest #3559
2 months ago
The first step for solving this equation is to distribute 3 through the parenthesis.
6y - 12 = 8y + 9 - 9y
Collect the like terms with y.
6y - 12 = -y + 9
Move the variable to the left side and then change its sign.
6y + y - 12 = 9
Now move the constant to the right side and change its sign.
6y + y = 9 + 12
Add the terms on the left side of the equation.
7y = 9 + 12
Add the numbers on the right side.
7y = 21
Lastly,, divide both sides of the equation by 7 to find your final answer.
y = 3
This means that y = 3 is the correct answer to your question.
Let me know if you have any further questions.
:)

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