Jeremy, Sue, and Holly are siblings. Sue was born three years before Holly,

Jeremy, Sue, and Holly are siblings. Sue was born three years before Holly, and Jeremy was born five years before Sue. The product of Sue's age and Jeremy's age is at most 150. If x represents the age of Holly, which inequality can be used to find the age of each sibling?

2 months ago

Solution 1

Guest Guest #4080
2 months ago

Answer:

Inequality to find the age of siblings is x²+ 11x + 24 ≤ 150.

Step-by-step explanation:

Let the age of Holly is x years. Now from the statements of the question we will form the equations.

Sue was born three years before Holly.

Sue = Holly + 3 = x + 3------(1)

Jeremy = Sue + 5

From equation (1)

Jeremy = (x + 3) + 5 = x + 8------(2)

Now statement says the product of Sue's age and Jeremy's age is at most 150.

Sue × Jeremy ≤ 150

(x + 3)(x + 8) ≤ 150

x² + 11x + 24 ≤ 150

Therefore inequality x² + 11x + 24 ≤ 150 can be used to find the age of each sibling.

Solution 2

Guest Guest #4081
2 months ago

Answer: x^2+11x+24 </= 150


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It said I have to have at least 20 characters to explain it well so here.
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