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Nancy wove a pot holder with a area of 80 square inches. The lengths and

Nancy wove a pot holder with a area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions make the most sense for a potholder? Explain

2 months ago

Solution 1

Guest Guest #3198
2 months ago
The pairs of numbers that multiply up to 80 are (1, 80), (2, 40), (4, 20), (5,16), and (8,10).
Since pot holders are normally close to squares, 8 by 10 makes the most sense

📚 Related Questions

Question
A right triangle has one side, s, and a hypotenuse of 12 meters. Find the area of the triangle as a function of s. A) A(s) = 2s 144 - s2 B) A(s) = s 144 - s2 C) A(s) = 2s 12 - s2 D) A(s) = 12s 144 - s2 10) The base of a ladder is placed 5 feet away from a 13 foot tall wall. What is the minimum length ladder needed to reach the top of the wall (rounded to the nearest foot)? A) 12 ft B) 13 ft C) 14 ft D) 15 ft
Solution 1
Part a)
we know that
area of triangle=b*h/2
b=s
applying the Pythagoras theorem
h²=12²-s²--------> h=√(144-s²)
so
A=(1/2)*s*√(144-s²)
Part b)
applying the Pythagoras theorem
c²=a²+b²
in this problem
c is the minimum length ladder needed to reach the top of the wall
a=5 ft
b=13 ft
so
 c²=5²+13²-----> c²=194--------> c=13.93 ft-------> c=14 ft

the answer is 
14 ft
Question
A right triangle has one side, s, and a hypotenuse of 12 meters. Find the area of the triangle as a function of s. A) A(s) = 2s 144 - s2 B) A(s) = s 144 - s2 C) A(s) = 2s 12 - s2 D) A(s) = 12s 144 - s2 10) The base of a ladder is placed 5 feet away from a 13 foot tall wall. What is the minimum length ladder needed to reach the top of the wall (rounded to the nearest foot)? A) 12 ft B) 13 ft C) 14 ft D) 15 ft
Solution 1

Answer: A(s) = \frac{s\sqrt{144-s^{2} } }{2} ; 10) c) 14ft

Step-by-step explanation:  Area of a triangle is: A = \frac{b.h}{2}

where:

b is base of a triangle

h is height of a triangle

For this right triangle, it is known one side, s, and hypotenuse, 12. To determine the other side, we use Pythagoras Theorem:

hypotenuse² = side² + side²

12^{2} = s^{2} + x^{2}

x^{2} = 12^{2} - s^{2}

x^{2} = 144 - s^{2}

x = \sqrt{144 - s^{2} }

To determine the Area of the right triangle as function of s:

A = \frac{b.h}{2}

A = \frac{1}{2}(s.x)

A = \frac{1}{2} . (s.\sqrt{144 - s^{2} })

Therefore, the area of the right triangle is:

A = \frac{1}{2} . (s.\sqrt{144 - s^{2} })

The ladder and the wall form a right triangle. The height of it is 13 ft, the base is 5ft and the hypotenuse is the length of the ladder. So, to find the minimum length, use Pythagoras Theorem:

hypotenuse² = side² + side²

h² = 13² + 5²

h² = 169 + 25

h = \sqrt{194}

h = 14

The minimum length the ladder has to have to reach the top is 14 ft.

Solution 2
A(s) equals 1/2 s square root of 144 minus s squared.. As s and r are the sides and the area of the triangle are 1/2(s)(r)
Question
What is the ratio of 5 gallons blue paint to 9 gallons of yellow paint?
Solution 1
Wouldn't you divide? If so, 5/9 = 0.6
Solution 2
The ratio would be 1:1.8 (1 to 1.8).

This can be found by dividing 5 by 5 ( making the ratio say 1 to...) and dividing 9 by 5 giving you 1.8. Thus makin* the ratio 1:1.8 or 1 to 1.8.

I hope this helps!

Question
Simplify x to the 5/8 over x to the 1/8
Solution 1
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\\\
\textit{}a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}
\\\\
-------------------------------

\bf \cfrac{x^{\frac{5}{8}}}{x^{\frac{1}{8}}}\implies x^{\frac{5}{8}}\cdot x^{-\frac{1}{8}}\implies x^{\frac{5}{8}-\frac{1}{8}}\implies x^{\frac{4}{8}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}
Question
How many times are equal to 40000 pounds
Solution 1
1 pound × 40,000 = 40,000 pounds.

Please mark as brainliest. I really need it.
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Draw 8 lines that are between 1inch and 3 inches long
Solution 1
This is not something we can really help you with, you'll have to do on your own paper. Just get a ruler and draw 8 different lines that measure 1-3 inches.
Question
I NEED HELP STAT PLZ PLZ PLZ Betty has between $40$ and $50$ pennies that she wants to arrange in a rectangular array. She notices she can arrange the pennies in three different ways without any gaps or spaces. However, if Betty adds two more pennies to her collection, she can only arrange the pennies in one way without any gaps or spaces: a straight line. How many pennies does Betty have?
Solution 1
If she adds two pennies, she can only arrange the pennies in a straight line.
A straight line is one penny wide. If she adds two pennies she ends up with a prime number of pennies.

Since she has between 40 and 50 pennies, she can have 41, 42, 43, 44, 45, 46, 47 ,48, or 49  pennies.

41 + 2 = 43 prime
42 + 2 = 44 not prime
43 + 2 = 45 not prime
44 + 2 = 46 not prime
45 + 2 = 47 prime
46 + 2 = 48 not prime
47 + 2 = 49 not prime
48 + 2 = 50 not prime
49 + 2 = 51 not prime

Only 43 and 47 are prime.
That means she has 41 or 45 pennies.
41 is prime, so it cannot be arranged in any other way than a straight line 1 by 41.
Let's look at 45.

45 = 3 * 3 * 5

45 = 9 * 5 = 3 * 15 = 45 * 1

She has 45 pennies.
Solution 2

Answer:

.

Step-by-step explanation:

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Solution 1
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Question
A cone with radius 2 feet and height 8 feet is shown.
Solution 1
The correct question is
What is the volume of a cone (in cubic feet) with a radius of 2 feet and a height of 8 feet?
Use 3.14 for π. Round your answer to the nearest hundredth

we know that
volume of a cone=(1/3)*pi*r²*h
r=2 ft
h=8 ft
volume of a cone=(1/3)*pi*2²*8-----> 33.49 ft³

the answer is
33.49 ft³

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ralph is a electrician he charges an initial fee of 24$ , plus 24 per hour. If ralph earned 144$ on the job , how long did the job take.
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It took him 5 hours
Solution 2
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