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W= { x / x is an integer and x > 3}

2 months ago

Guest #9847975

2 months ago

For this, we will use roster notation.

We know that x has to be an integer, which is any number not a fraction. We also know that x is greater than 3, but not equal to it, therefore 3 will not be included. Our set will start with 4.

Since there are many, many integers greater than 3, we only have to list the first 5 and then add "..." to show the pattern continues.

**W = {4, 5, 6, 7, 8, ...}**

We know that x has to be an integer, which is any number not a fraction. We also know that x is greater than 3, but not equal to it, therefore 3 will not be included. Our set will start with 4.

Since there are many, many integers greater than 3, we only have to list the first 5 and then add "..." to show the pattern continues.

Question

I need help with this problem. 2.9 Ã— 10 ^11 - 3.7 Ã— 10^13

Solution 1

[tex]2.9\times10^{11}-3.7\times10^{13}=2.9\times10^{11}-3.7\times10^2\times10^{11}\\\\=10^{11}\times(2.9-3.7\times10^2)=10^{11}\times(2.9-3.7\times100)\\\\=10^{11}\times(2.9-370)=-367.1\times10^{11}=-3.671\times10^{13}[/tex]

Question

I know how to do equivalent fractions but idk how to do this one

Solution 1

Reduce your fraction 2/4 down to 1/2, and then find the smallest common factor of 2 and 6 (which happens to be 6). Since you multiply 2 by 3, then you have to multiply your numerator by 3 also, giving you 3/6. Since your denominators match, it means you have found the answer.

Solution 2

2/4 = x/6

2/4 = 1/2 = 3/6

you find the least common denominator which will be 12

2/4 = 6/12

you multiply 4 x 3 to get 12 so you have to multiply 2 x 3 and get 6.

now if youÂ divideÂ both numbers 6/12Â by 2 then 6/12=1/2.

another way to look at this one is 2 is half of 4, so what is half of 6.

../.... = .../......

Question

You travel 60 kilometers in 1.5 hours. What is your average speed?

Solution 1

technically you could write 60km/1.5hr but I think you meant km/hr.

So your traveling 60km every 1.5hours but you only want to know how much every one hour. think of 1.5 as 150% of what you want (which is one) take 60 divide it into one hundred pieces (60/150) then multiply buy 100% of what you want (quotient of last problem * 100)

final equation looks like this (60/150) 100 = 40 km/ hr

Ps. *=multiply

So your traveling 60km every 1.5hours but you only want to know how much every one hour. think of 1.5 as 150% of what you want (which is one) take 60 divide it into one hundred pieces (60/150) then multiply buy 100% of what you want (quotient of last problem * 100)

final equation looks like this (60/150) 100 = 40 km/ hr

Ps. *=multiply

Solution 2

Your average speed is 60 km per 1.5 hours. In a somewhat more popular unit, it's 60/1.5=40 km/hr.

Question

f(x)={1/2x-2, if xâ‰¥0}

Â Â Â Â Â {3/4x+3, if x<0}

Graph this equation?

I don't understand how to do this.

Â Â Â Â Â {3/4x+3, if x<0}

Graph this equation?

I don't understand how to do this.

Solution 1

[tex]f(x)= \left\{\begin{array}{ccc}\frac{1}{2}x-2&if\ x\geq0\\\frac{3}{4}x+3&if\ x < 0\end{array}\right\\------------------\\x < 0\to f(x)=\frac{3}{4}x+3\\\\for\ x=-4\to y=\frac{3}{4}(-4)+3=-3+3=0\to(-4;\ 0)\\for\ x=0\to y=\frac{3}{4}(0)+3=3\to(0;\ 3)\\------------------------\\x\geq0\to f(x)=\frac{1}{2}x-2\\\\for\ x=0\to y=\frac{1}{2}(0)-2=-2\to(0;-2)\\for\ x=4\to y=\frac{1}{2}(4)-2=2-2=0\to(4;\ 0)\\------------------------------\\Look\ at\ the\ picture.[/tex]

Question

* Use for question 4-6 *

The expression 16t2 models the distance in feet that an object falls during t seconds after being dropped. Find the distance an object falls during each time.

4) .25 sec 5) .5 sec 6) 2 sec

need helpp

The expression 16t2 models the distance in feet that an object falls during t seconds after being dropped. Find the distance an object falls during each time.

4) .25 sec 5) .5 sec 6) 2 sec

need helpp

Solution 1

16ft.(.25s)2

4ft/s*2

8ft/s

16ft(.5s)2

8ft/s * 2

16ft/s

16ft(2s)2

32ft/s * 2

64ft/s

ft =feet

s =second(s)

/ =per

4ft/s*2

8ft/s

16ft(.5s)2

8ft/s * 2

16ft/s

16ft(2s)2

32ft/s * 2

64ft/s

ft =feet

s =second(s)

/ =per

Question

Round 157 to the nearest ten

Solution 1

160

because 157 is closer to 160 than 150

because 157 is closer to 160 than 150

Solution 2

If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

**15****7**** â‰ˆ**** 160**

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

Question

Solve for x 3(8x-5)=-4(7-6x)

Solution 1

3(8x - 5) = -4(7 - 6x)

Distribute 3 and -4 inside their respective parentheses.

24x - 15 = -28 + 24x

Add 28 to both sides.

24x + 13 = 24x

Subtract 24x from both sides.

13 = 0

This is an untrue statement, so that means there are no solutions to this equation.

Your answer is **no solution.**

Solution 2

**Answer: **

no solution

**Step-by-step explanation:**

I did this question on my homework and I got it correct

Hope this helps! ;)

Question

Â Find the midpoint of the segment joining the points: (4, -2) and (-8, 6) Hint: Formula for midpoint is (x1+x2)/2, (y1+y2)/2Â

Solution 1

[tex](4;-2);\ (-8;\ 6)\\\\the\ midpoint:\left(\frac{4+(-8)}{2};\ \frac{-2+6}{2}\right)\to\left(\frac{4-8}{2};\ \frac{4}{2}\right)\to\left(\frac{-4}{2};\ \frac{4}{2}\right)\to(-2;\ 2)[/tex]

Solution 2

**Answer:**

(-2, 2)

**Step-by-step explanation:**

Look at the image down below!! (ï¾‰â—•ãƒ®â—•)ï¾‰*:ï½¥ï¾Ÿâœ§

Question

What is negative five over eight -5/8 b = 10

Solution 1

[tex]- \frac{5}{8}\cdot b = 10 \ \ \ |multiply\ both\ sides\ by\ (-\frac{8}{5}) \\\\(-\frac{8}{5})\cdot (- \frac{5}{8})\cdot b =(-\frac{8}{5})\cdot 10\\\\b=(-8)\cdot 2\\\\b=-16[/tex]

Question

solve and reduce to lowest term 5 1/2- 2/3

Solution 1

[tex]5 \frac{1}{2}- \frac{2}{3}= 5 \frac{3}{6}- \frac{4}{6}=4\frac{9}{6}-\frac{4}{6}=4\frac{5}{6}[/tex]

Solution 2

5 1/2 - 2/3

11/2 - 2/3

33/6 - 4/6

29/6

11/2 - 2/3

33/6 - 4/6

29/6

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