What are the domain and range of f(x) = 2(3x)?

What are the domain and range of f(x) = 2(3x)?

2 months ago

Solution 1

Guest Guest #3393
2 months ago
Its going to be all real numbers

or (- inf , inf) 

Solution 2

Guest Guest #3394
2 months ago


A) domain (-infinity, infinity); range (0, infinity)

Step-by-step explanation:

Domain is reading the x-axis left or right

Range is reading the y-axis up or down

Hope this helps!

📚 Related Questions

Simplify the following expression.
Solution 1
The first step for solving this expression is to express with a positive exponent using  a^{-n} X  \frac{1}{ a^{2}}  X b.
4 ×  \frac{1}{ a^{2} }  × b
Now calculate the product.
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Before you get your final answer,, you must remember that any expression multiplied by 1 stays this same. This makes our final answer the following:
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Let me know if you have any further questions.
Solution 2

Answer: C

Step-by-step explanation:

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Circle J has center J (4,-3) and radius 5 What is the measure, in degrees, of the arc with endpoints A (9,-3) and B (4,2)? Explain the process you used (in words) and include the work you did to find this answer.
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This would be a 90° arc.

To find this, we can find the measure of the central angle that intercepts the arc.

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The intercepted arc has a measure equal to that of the central angle, so the arc is also 90°.
Is y=-13/6x+5/3 same as 13x+6y=10 ?
Solution 1
13x + 6y = 10
-13x        -13x
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Divide 6y, 13x, and 10 by 6

y = -13/6x + 10/6

Simply 10/6 by finding the least common multiple of the numerator and denominator, which is 2. 10 divided by 2 is 5, and 6 divided by 2 is 3. 10/6 = 5/3

y = -13/6x + 5/3
Help How much will $5,000 invested at 6% compounded annually amount to after 10 years?
Solution 1
To find one year, here's the equation:
5000 + 0.06(5000)
For 10 years:
5000 + 10(0.06(5000))
5000 + 0.6(5000)
We can make it smaller:
1.6(5000) = 8000
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What does 3P2 equal?
Solution 1

No one has mentioned, so I 
will. What you are looking for is the permutation of 3 things taken 2 at a time. In other words, how many different unique ways are there to arrange 3 items, say colored balls, taking 2 of them for each group. By unique, I mean that 1 red and 1 blue is the same as 1 blue and 1 red,
Solve the equation 2 cos x + 1 = 0 , 0 <= x <= 2pi PLEASE HELP! WILL AWARD!
Solution 1
It would be pi over 6, 5 pi over 6, and 3 pi over 6.
Solution 2
Im not saying its right but I got 0,3,3,and2π  f(x)=2cos2xcosx−1=0
Solve this quadratic equation for cos x.
Since a + b + c = 0, use shortcut.
One real root is cos x = 1 and the other is cosx=ca=−12.
Trig table and unit circle -->
a. cos x = 1 --> arc x = 0, and arc x=2π
b. cosx=−12 --> arc x=±3
The arc −2π3 is co-terminal to the arc: 3
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Evaluate 3P4, I didn’t understand this question but if you know it would great if you could explain!!! 15,120 36 3,024 504
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Solution 2



Step-by-step explanation:

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determine the amount of an investment if $400 is invested at an annual interest rate of 7.25% for 7 years. round to the nearest penny.
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Equation for one year:
But we have 7 years:
Multiply in the parentheses
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The equation for a projectile's height versus time is h(t)=-16t^2+Vt+h. A tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an initial speed of 130 feet per second. Which equation correctly models the ball's height as a function of time?
Solution 1

The maximum height at the moment is 266.0625 ft.

Projectile's height

The equation for a projectile's height versus time is

&h(t)=-16 t^{2}+V  t+h  \\

h = 2

V = 130

Substitute these values into the function

$h(t)=-16 t^{2}+130 t+2$

Take the first derivative

$h^{\prime}(t)=-16* 2 t+130

=-32 t+130$

Equate the derivative with zero $h^{\prime}(t)=0$.

Solve the equation -32 t + 130=0

32 t = -130

t = -130 /(-32)

= 4.0625(s) .

Find the maximum height at the moment

t = 4.0625 (s)

h(4.0625) = -16(4.0625)^{2}+130 * 4.0625+2

= - 264.0625+528.125+2

= 266.0625 ft.

Therefore, the maximum height at the moment is 266.0625 ft.

To learn more about projectile's height



Solution 2
For this case we must use the projectile equation for this problem.
 We have then:
 h (t) = - 16t ^ 2 + Vt + h
 V: initial speed
 h: height
 For the tennis ball we have:
 h (t) = - 16t ^ 2 + 130t + 2
An equation that correctly models the ball's height as a function of time is:
h (t) = - 16t ^ 2 + 130t + 2